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Learning Introductory Physics with Activities

Section 18.10 Thin Coatings

Subsubsection Activities

Activity 18.10.1. Warm-up.

Recall the Thin-film Figure, in which light is incident on a thin surface with a different index of refraction than the neighboring surfaces.
(a)
A common assumption when considering thin-film interference is for the incident light to be nearly normal to the surface. How does this assumption simplify the situation?
(b)
How would you redraw the figure to represent the situation more accurately? Why do you think the figure is drawn the way it is?
(c)
What is the path length difference between rays 2 and 5 for the light traveling through the thin film to the right?
(d)
What is the phase difference due to the path length difference for the rays 2 and 5 traveling through the thin film to the right?
(e)
When light reflects off a material of a higher index of refraction, the reflected wave is inverted, which can be represented as a phase shift of \(\pi\text{.}\) How does this compare to other situations you have seen in which a reflected wave is inverted? Check your answere in Boundaries

Activity 18.10.2. The Screen Coating.

A thin layer of \(\mathrm{TiO_2}\) with \(n \approx 2.6\) is a common coating for the glass screen of an electronic device \(n \approx 1.5\text{.}\)
(a)
For each reflection, identify how (if at all) the phase of the reflected light will shift.
(b)
How thick should the coating be to cause complete destructive interference for light with a wavelength of 520 nm? (Hint: Use your expressions from the previous activity!)
(c)
After some testing, you see that the thin coating breaks down too fast when it is this thin. What are other thicknesses that would still produce the desired result?

Activity 18.10.3. Simulation.

Visit this simulation and use it to check how your answer would change if you adjusted the material out of which the thin coating was made.