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Section 11.13 LC Circuits
Recall that the voltage across an inductor is given by
\begin{equation*}
V_{inductor} = -L \frac{dI}{dt}
\end{equation*}
Exercises Activities
Figure 11.13.1. A circuit with a charged capacitor and an inductor.The circuit above contains a capacitor and an inductor. The capacitor is initially charged (positive on the top and negative on the bottom).
1.
When the switch is closed, the initial current through the inductor is 0 A. Give a physical reason for why you think this happens.
