You are stationary on the ground, watching as a person walks past you traveling east at \(\vec{v}_{p,g} = +5 \hat{x} \mathrm{~km/hr}\) toward the front of an airplane which is traveling west at \(\vec{v}_{a,g} = -150 \hat{x} \mathrm{~km/hr}\text{.}\) The first subscript (\(p\) and \(a\)) represents the object, while the second (\(g\)) indicates that these velocities are given relative to the ground’s reference frame. Since this also happens to be your reference frame, your velocity is \(\vec{v}_{y,g} = 0 \mathrm{~km/hr}\text{.}\)
From the walking person’s perspective, you are traveling with velocity \(\vec{v}_{y,p} = \vec{v}_{y,g} - \vec{v}_{p,g} = -5 \hat{x} \mathrm{~km/hr}\text{,}\) while the airplane is traveling with velocity \(\vec{v}_{a,p} = \vec{v}_{a,g} - \vec{v}_{p,g} = -155 \hat{x} \mathrm{~km/hr}.\)
See if you can determine your velocity and the walking person’s velocity relative to the airplane!