Skip to main content

Learning Introductory Physics with Activities

Section 1.8 The Cross Product

Figure 1.8.1. Introducing the cross product.
In a previous section you learned about the dot product as one way to multiply vectors. Another way to multiply vectors is the cross product, named because you will use \(\times\) to represent the multiplication. Unlike the dot product, the cross product of two vectors is a vector, not a scalar.

Definition 1.8.2. The Cross Product.

The magnitude of the cross product between two vectors is given by \(|\vec{A} \times \vec{B}| = AB \sin\theta\text{,}\) where \(\theta\) is the angle between the vectors when placed tail-to-tail. The direction is always perpendicular to both \(\vec{A}\) and \(\vec{B}\text{,}\) and is given by the right hand rule (see below).
Figure 1.8.3. A representation of vectors A and B and the angle between them illustrating the cross product for two vectors.
Here, \(\theta\) represents the angle between the two vectors when they are placed tail to tail. A and B represent the magnitudes of the vectors \(\vec{A}\) and \(\vec{B}\text{.}\)
Figure 1.8.4. Introducing the right hand rule.
Conceptually, the magnitude of the cross product quantifies how perpendicular two vectors are. The magnitude of the cross product is the magnitude of \(\vec{B}\) multiplied by the projection of \(\vec{A}\) perpendicular to\(\vec{B}\text{.}\) You can think of a projection as the length of the shadow that \(\vec{A}\) would cast perpendicular to \(\vec{B}\) if you were to shine a light from above.
Figure 1.8.7.

Exercises Practice Activities

1.

Indicate the direction of the cross product of the two vectors in the figure above, \(\vec{A} \times \vec{B}\text{.}\)
Answer.
Into the screen!
Use the two vectors shown below for the remaining questions.
Figure 1.8.8.

2.

Indicate the direction of the cross product \(\vec{v}_1 \times \vec{v}_2\text{.}\)
Answer.
Into the screen again!

3.

Label the appropriate angle \(\theta\) and estimate its value. Use your estimate and the value \(a = 15\) for the magnitude of both vectors to estimate the magnitude of \(\vec{v}_1 \times \vec{v}_2\text{.}\)
Answer.
Estimating the angle to be about \(120^o\) gives a cross product with a magnitude of about \(195\text{.}\)