A rectangular surface measures 2.0 m x 4.0 m and lies in the xy-plane. Find the electric flux through the surface if the E-field is given by: \(\vec{E} = (2.0 \hat{x} - 3.0 \hat{z}) \frac{\mathrm{N}}{\mathrm{C}}\)
No. Gauss’s Law tells us that the net electric flux through a surface is equal to the charge enclosed (divided by \(\epsilon_o\)). To use Gauss’s Law, you need to take advanage of the symmetry of the charge distribution. If a Gaussian surface is drawn around both charges, the charge enclosed is zero, so the net flux is zero. There is not a useable symmetry for the dipole.
Two concentric spherical surfaces enclose a point charge q. The radius of the outer sphere is twice that of the inner one. Compare the electric fluxes crossing the two surfaces.