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Learning Introductory Physics with Activities

Section 22.6 Practice - Symmetry

Calculation 22.6.1. Flux Through a Rectangle.

A rectangular surface measures 2.0 m x 4.0 m and lies in the xy-plane. Find the electric flux through the surface if the E-field is given by: \(\vec{E} = (2.0 \hat{x} - 3.0 \hat{z}) \frac{\mathrm{N}}{\mathrm{C}}\)
Answer.
\(\Phi_E = -24 \frac{\mathrm{Nm}^2}{\mathrm{C}}\)

Calculation 22.6.2. Greatest Total Flux.

Figure 22.6.1. Charges in Gaussian surfaces.
Which rectangular Gaussian Surface in the figure above has the greatest total flux?
Answer.

Calculation 22.6.3. Gauss’s Law for a Dipole.

Would Gauss’s law be helpful for determining the electric field of a dipole? Why?
Answer.
No. Gauss’s Law tells us that the net electric flux through a surface is equal to the charge enclosed (divided by \(\epsilon_o\)). To use Gauss’s Law, you need to take advanage of the symmetry of the charge distribution. If a Gaussian surface is drawn around both charges, the charge enclosed is zero, so the net flux is zero. There is not a useable symmetry for the dipole.

Calculation 22.6.4. Different Gaussian Surfaces.

Two concentric spherical surfaces enclose a point charge q. The radius of the outer sphere is twice that of the inner one. Compare the electric fluxes crossing the two surfaces.
Answer.
Since the electric field has a \(1/r^2\) dependence, the fluxes are the same since \(A = 4\pi r^2\text{.}\)

Calculation 22.6.5. Net Electric Flux.

A point charge of 10 \(\mu\)C is at an unspecified location inside a cube of side 2 cm. Find the net electric flux though the surfaces of the cube.
Answer.
\(\Phi_E = 1.13 \times 10^{6} \ \frac{\mathrm{Nm}^2}{\mathrm{C}}\)

References References

[1]
Practice activities provided by Kathy Hadley: http://khadley.com/Courses/Physics/ph_213/topics/gauss/.
[2]
Practice activities provided by Ling, S. J., Moebs, W., & Sanny, J. (2016). Electric Potential, Gauss’s Law. In University Physics Volume 2. OpenStax.